If 7sin2θ + 3cos2θ= 4, 0° < θ < 90° than the value of sin 2θ is?

1 \(\frac{√3}{4}\)  \(\frac{√3}{2}\)  \(\frac{2}{√3}\)

\(\frac{√3}{2}\)

θ = 30° satisfying the equation. So, put θ = 30° sin2θ = sin 60° = \(\frac{√3}{2}\)