Two electrons are in n = 1 and n = 3 orbits respectively. Find the ratio of their energies.
Answer & explanation
Correct answer: option 1
Total energy : E = \(\frac{-13.6}{n^2}\) eV
$ \Rightarrow E \propto \frac{1}{n^2}$
$\Rightarrow \frac{E_1}{E_3}= \frac{3^2}{1^2} = 9:1$