Practicing Success
Practicing Success
CUET Preparation Today
Two electrons are in n = 1 and n = 3 orbits respectively. Find the ratio of their energies. |
9:1 1:9 1:3 3:1 |
9:1 |
Total energy : E = \(\frac{-13.6}{n^2}\) eV $ \Rightarrow E \propto \frac{1}{n^2}$ $\Rightarrow \frac{E_1}{E_3}= \frac{3^2}{1^2} = 9:1$ |
