A uniform metallic wire of resistance $4 \Omega$ is bent to form a circle. What is the effective resistance between the end of its diameter? |
$1 \Omega$ $2 \Omega$ $4 \Omega$ $8 \Omega$ |
$1 \Omega$ |
The correct answer is Option (1) → $1 \Omega$ When a wire is bent into circle, the current splits equally between two halves of the wire, when measured between the ends of the diameter. $R_{half}=\frac{R}{2}=\frac{4}{2}=2Ω$ R → Resistance of wire When connected in parallel, $R_{eff}-R_{half}+R_{half}⇒R_{eff}=\frac{R_{half}}{2}=\frac{2}{2}$ $R_{eff}=1Ω$ |