The momentum of photon of electromagnetic radiation is \( 3.3\times10^{-29}\,\mathrm{kg\,m\,s^{-1}} \). The frequency of the waves associated with it would be - (use \( h=6.6\times10^{-34}\,\mathrm{J\,s} \))
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → \( 1.5\times10^{13}\,\mathrm{Hz} \)
The momentum of a photon is \( p = \frac{h}{\lambda} = \frac{h\nu}{c} \), so the frequency follows from the momentum. Taking \( c = 3\times10^{8}\,\mathrm{m\,s^{-1}} \):
\( \displaystyle \nu = \frac{pc}{h} = \frac{3.3\times10^{-29}\times3\times10^{8}}{6.6\times10^{-34}} \)
\( \displaystyle \nu = \frac{9.9\times10^{-21}}{6.6\times10^{-34}} = 1.5\times10^{13}\,\mathrm{Hz} \)
Note: A similar question was also asked in CUET (UG) 2025 on 28-05-2025 (Slot 2).