Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Dual Nature of Radiation and Matter

Question:

In an experiment on photoelectric effect the frequency v of the incident light is plotted against the stopping potential V0. The work function of the photoelectric surface is given by (e is electronic charge):

Options:

OB × e in eV

OB in volt

OA in eV

The slope of the line AB

Correct Answer:

OB × e in eV

Explanation:

According to Einstein’s equation, $hv = \phi_0 + K_{max}$

Where, $\phi_0$ is the work function.

$⇒hv=\phi_0+eV$

$⇒V_0=\frac{hv}{e}+\frac{\phi_0}{e}$

Comparing with equation, y = mx + c

$\phi_0$ =–(intercept) × e = OB × e in eV