In an experiment on photoelectric effect the frequency v of the incident light is plotted against the stopping potential V0. The work function of the photoelectric surface is given by (e is electronic charge):
Answer & explanation
Correct answer: option 1
According to Einstein’s equation, $hv = \phi_0 + K_{max}$
Where, $\phi_0$ is the work function.
$⇒hv=\phi_0+eV$
$⇒V_0=\frac{hv}{e}+\frac{\phi_0}{e}$
Comparing with equation, y = mx + c
$\phi_0$ =–(intercept) × e = OB × e in eV