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Inequations $3 x-y \geq 3$ and $4 x-y>4$ |
Have solution for positive $x$ and $y$ Have no solution for positive $x$ and $y$ Have solution for all $x$ Have solution for all $y$ |
Have solution for positive $x$ and $y$ |
Following figure will be obtained on drawing the graphs of given inequations :
From $3 x-y \geq 3, \frac{x}{1}+\frac{y}{-3}=1$ From $4 x-y \geq 4, \frac{x}{1}+\frac{y}{-4}=1$ Clearly the common region of both the inequations is true for positive value of (x, y). It is also true for positive values of x and negative values of y. |
