Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B2

Chapter

Algebra

Question:

If $\left[\begin{array}{ccc}3 & 2 x+5 y & -2 \\ x+4 y & 7 & -5\end{array}\right]=\left[\begin{array}{rrr}3 & 10 & -2 \\ 2 & 7 & -5\end{array}\right]$. Then the values of x and y are:

Options:

$x=-2, y=6$

$x=12, y=5$

$x=-4, y=7$

$x=10, y=-2$

Correct Answer:

$x=10, y=-2$

Explanation:

The correct answer is Option (4) - $x=10, y=-2$