If $\left[\begin{array}{ccc}3 & 2 x+5 y & -2 \\ x+4 y & 7 & -5\end{array}\right]=\left[\begin{array}{rrr}3 & 10 & -2 \\ 2 & 7 & -5\end{array}\right]$. Then the values of x and y are: |
$x=-2, y=6$ $x=12, y=5$ $x=-4, y=7$ $x=10, y=-2$ |
$x=10, y=-2$ |
The correct answer is Option (4) - $x=10, y=-2$ $\begin{bmatrix} 3 & 2x+5y & -2 \\ x+4y & 7 & -5 \end{bmatrix} = \begin{bmatrix} 3 & 10 & -2 \\ 2 & 7 & -5 \end{bmatrix}$ $2x + 5y = 10$ $x + 4y = 2$ $x = 2 - 4y$ $2(2 - 4y) + 5y = 10$ $4 - 8y + 5y = 10$ $4 - 3y = 10$ $-3y = 6 \Rightarrow y = -2$ $x = 2 - 4(-2) = 2 + 8 = 10$ The values are $x = 10,\; y = -2$. |