The correct relation between the transistor parameters α and β is:

The correct answer is Option (2) → \( \displaystyle \beta=\frac{\alpha}{1-\alpha} \)

The current gain in the common-base arrangement is \( \alpha = I_C/I_E \) and in the common-emitter arrangement is \( \beta = I_C/I_B \). The three currents of a transistor are related by \( I_E = I_B + I_C \).

    \( \displaystyle \beta = \frac{I_C}{I_B} = \frac{I_C}{I_E - I_C} \)

Dividing the numerator and the denominator by \( I_E \):

    \( \displaystyle \beta = \frac{I_C/I_E}{1 - I_C/I_E} = \frac{\alpha}{1 - \alpha} \)