A cricketer has a certain average runs for 10 innings. In the 11th inning, he scores 100 runs, now his average is increased by 9 runs. Then average of 11 innings is: |
10 runs 20 runs 11 runs 21 runs |
10 runs |
Let the old average of the cricketer be x. According to the question: \(\frac{\text{10x + 100} }{11 }\) = x + 9 10x + 100 = 11x + 99 x = 1 The old average of the cricketer comes out to be 1. Thus, the new average = x + 9 = 1 + 9 = 10 runs. |