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CUET Preparation Today
If cot43θ + tan43θ = 2, find 2sin2θ + cos4θ. |
1 2 \(\frac{5}{4}\) \(\frac{3}{4}\) |
\(\frac{5}{4}\) |
If cotnθ + tannθ = 2 then cotθ = tanθ = 1 where θ = 45° Now, ⇒ 2sin2θ + cos4θ = 2 × (\(\frac{1}{\sqrt {2}}\))2 + (\(\frac{1}{\sqrt {2}}\))4 = 2 × \(\frac{1}{2}\) + \(\frac{1}{4}\) = 1 + \(\frac{1}{4}\) = \(\frac{5}{4}\) |
