A and B are two points on a circle with centre O. C is a point on the minor are of the circle between points A and B. The tangents to the circle at A and B meet each other at a point D. If ∠ADB = 25° , then ∠ACB (in degrees)is equal to:
Answer & explanation
Correct answer: option 3
We have,
∠ADB = 25°
Now, according to the question,
∠ACB = 90o + \(\frac{25}{2}\) = 102.5o