A and B are two points on a circle with centre O. C is a point on the minor are of the circle between points A and B. The tangents to the circle at A and B meet each other at a point D. If ∠ADB = 25° , then ∠ACB (in degrees)is equal to:

102.5

We have,

∠ADB = 25°

Now, according to the question,

∠ACB = 90^o + \(\frac{25}{2}\) = 102.5^o