For an AC circuit, a phase diagram shows emf on X-axis, and current I is at angle θ to emf. Angle is phase angle θ between emf and current. Current I is resolved into two components, I cos θ is along emf on X-axis. I sine is along perpendicular direction to emf. (A) Component I cos θ will draw the power from the source Choose the correct answer from the options given below: |
(B) and (C) only (A) and (C) only (C) and (D) only (A) and (D) only |
(A) and (D) only |
The correct answer is Option (4) → (A) and (D) only Given: In an AC circuit, current lags or leads emf by phase angle θ. Current components: • $I \cos \theta$ → component of current in phase with emf (active component) • $I \sin \theta$ → component of current perpendicular to emf (reactive component) Power is given by: $P = E I \cos \theta$ Hence, (A) Component $I \cos \theta$ will draw the power from the source — ✔ True (B) Component $I \sin \theta$ will draw the power from the source — ✖ False (C) $I \cos \theta$ is called the powerless current — ✖ False (it is the power component) (D) $I \sin \theta$ is called the powerless current — ✔ True Final Answer: (A) and (D) |