CUET Preparation Today
The magnetic flux linked with a coil is given by an equation $\Phi=\left(8 t^2+3 t+5\right) Wb$ The induced emf in the coil at t = 4s will be: |
16 V 39 V 67 V 145 V |
67 V |
The correct answer is Option (3) → 67 V The induced emf (ε) in a coil is, $ε=-\frac{d\phi}{dt}=-\frac{d(8t^2+3t+5)}{dt}$ $=16t+3$ $ε(t=4)=(16×4+3)V$ $=67V$ |
