The magnetic flux linked with a coil is given by an equation
$\Phi=\left(8 t^2+3 t+5\right) Wb$
The induced emf in the coil at t = 4s will be:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 67 V
The induced emf (ε) in a coil is,
$ε=-\frac{d\phi}{dt}=-\frac{d(8t^2+3t+5)}{dt}$
$=16t+3$
$ε(t=4)=(16×4+3)V$
$=67V$