If the length of a rectangle is increased by 20% and breadth decrease…

If length = l, breadth = b and  Area = lb

Then,

ATQ,

New length = \(\frac{6}{5}\) × l, New breadth = \(\frac{17}{20 }\)b

Now, New Area = \(\frac{6}{5}\)l × \(\frac{17}{20}\)b

                                = \(\frac{102}{100}\)lb

∴ Area increases by 2%