If the length of a rectangle is increased by 20% and breadth decreased by 15%, then area will be:

2% increase 2% decrease 4% increase remains unchanged

2% increase

If length = l, breadth = b and  Area = lb Then, ATQ, New length = \(\frac{6}{5}\) × l, New breadth = \(\frac{17}{20 }\)b Now, New Area = \(\frac{6}{5}\)l × \(\frac{17}{20}\)b                                 = \(\frac{102}{100}\)lb ∴ Area increases by 2%