In ΔABC, BD is the internal bisector of ∠B meeting AC at D. If CD = 7 cm and AC = 10.5 cm, then AB : BC |
2 : 3 1 : 2 3 : 4 3 : 2 |
1 : 2 |
BD is bisector of angle B In △BDA and △BDCAB/BC = AD/CD = (AC-CD)/CD = (10.5-7)/7 = 3.5/7 = 1:2 AB:BC = 1:2 The correct answer is Option (2) → 1 : 2 |