The demand function is $x=\frac{24-2p}{3}$ where x is the number of units demanded and p is the price per unit, then the price per unit for which the revenue is maximum is :

₹6

The correct answer is Option (3) → ₹6

Revenue is,

R = Price per unit (P) × No. of units (x)

$=P\left(\frac{24-2P}{3}\right)$

$=\left(\frac{24P-2P^2}{3}\right)$

$\frac{dP}{dR}=\frac{1}{3}[24-4P]=0$

$⇒4P=24⇒P=6$