Select the combination of letters that when sequentially placed in the gaps of the given letter series will complete the series.
a_bbc _cb_c a_b_c
Answer & explanation
Correct answer: option 3
There are 15 letters. If we break them in groups of 5 each. We will get like:
a_bbc / _cb_c / a_b_c
acbbc / acbbc / acbbc
So, cabcb