Select the combination of letters that when sequentially placed in the gaps of the given letter series will complete the series. a_bbc _cb_c a_b_c |
cabca cbaac cabcb caccb |
cabcb |
There are 15 letters. If we break them in groups of 5 each. We will get like: a_bbc / _cb_c / a_b_c acbbc / acbbc / acbbc So, cabcb |