Osmotic pressure of a solution is 0.0821 atm at a temperature of 300 K. The concentration in moles/litre will be:
Answer & explanation
Correct answer: option 3
The correct answer is option 3. \(0.3 \times 10^{-2}\).
To find the concentration of the solution in moles per liter (Molarity), we can use the formula relating osmotic pressure (\(\pi\)), molarity (\(M\)), the ideal gas constant (\(R\)), and temperature (\(T\)):
\(\pi = MRT\)
Given:
Osmotic pressure (\(\pi\)) = 0.0821 atm
Temperature (\(T\)) = 300 K
Ideal gas constant (\(R\)) = 0.0821 L·atm·K\(^{-1}\)·mol\(^{-1}\)
We need to solve for \(M\), the concentration in moles per liter.
1. Convert the temperature to Kelvin: \( T = 300 \) K
2. Substitute the given values into the formula:
\(0.0821 = M \cdot 0.0821 \cdot 300\)
3. Solve for \( M \):
\(M = \frac{0.0821}{0.0821 \cdot 300}\)
\(M = \frac{0.0821}{24.63}\)
\(M \approx 0.00333\)
\(M = 0.33 \times 10^{-2}\)
Therefore, the concentration of the solution in moles per liter is approximately \( 0.33 \times 10^{-2}\) M.