In a simultaneous throw of a pair of dice, what is the probability of getting a total more than 8?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \(\frac{5}{18}\)
Two dice give \(6\times6=36\) equally likely outcomes, one for each pair of faces. The probability is the number of outcomes with a total more than 8, that is 9, 10, 11 or 12, divided by 36.
Shaded cells: 4 with total 9, 3 with total 10, 2 with total 11 and 1 with total 12
Probability \(\displaystyle =\frac{4+3+2+1}{36}=\frac{10}{36}=\frac{5}{18}\)