CUET Preparation Today
The principal value of $cot^{-1}\left(\frac{-1}{\sqrt{3}}\right)$ is : |
$-\frac{2\pi }{3}$ $\frac{2\pi }{3}$ $\frac{\pi }{3}$ $-\frac{\pi }{3}$ |
$\frac{2\pi }{3}$ |
The correct answer is option (2) → $\frac{2\pi }{3}$ $\cot^{-1}\left(\frac{-1}{\sqrt{3}}\right)=\pi - \cot^{-1}\left(\frac{1}{\sqrt{3}}\right)$ $\pi - \frac{\pi}{3}=\frac{2\pi}{3}$ |
