What will be the emf induced in a square shaped coil of side 0.2 m having 200 turns, placed perpendicular to a magnetic field which is increasing at the rate of $0.5 Ts^{-1}$?

4.0 V

The correct answer is Option (3) → 4.0 V

Induced emf is

$\mathcal{E} = N \cdot A \cdot \frac{dB}{dt}$

Here, $N = 200$, $A = (0.2)^2 = 0.04 \, m^2$, $\frac{dB}{dt} = 0.5 \, T s^{-1}$

$\mathcal{E} = 200 \times 0.04 \times 0.5$

$\mathcal{E} = 4 \, V$

Final Answer: 4 V