Case : Read the passage and answer the question(s).

The energy of an atom is the least (largest negative value) when its electron is revolving in an orbit closest to the nucleus i.e., the one for which n = 1. For n = 2, 3, ... the absolute value of the energy E is smaller, hence the energy is progressively larger in the outer orbits. The lowest state of the atom, called the ground state, is that of the lowest energy, with the electron revolving in the orbit of smallest radius, the Bohr radius, a₀. The energy of this state (n = 1), E₁ is –13.6 eV. Therefore, the minimum energy required to free the electron from the ground state of the hydrogen atom is 13.6 eV. It is called the ionization energy of the hydrogen atom. This prediction of the Bohr’s model is in excellent agreement with the experimental value of ionization energy. At room temperature, most of the hydrogen atoms are in ground state. When a hydrogen atom receives energy by processes such as electron collisions, the atom may acquire sufficient energy to raise the electron to higher energy states. The atom is then said to be in an excited state.  For n = 2; the energy E₂ is –3.40 eV. It means that the energy required to excite an electron in hydrogen atom to its first excited state, is an energy equal to E₂ – E₁ = –3.40 eV – (–13.6) eV = 10.2 eV. Similarly, E₃ = –1.51 eV and E₃ – E₁ = 12.09 eV, or to excite the hydrogen atom from its ground state (n = 1) to second excited state (n = 3), 12.09 eV energy is required, and so on. From these excited states the electron can then fall back to a state of lower energy, emitting a photon in the process. Thus, as the excitation of hydrogen atom increases (that is as n increases) the value of minimum energy required to free the electron from the excited atom decreases. 

What is the energy of an electron in the hydrogen atom in 3^rd excited state?

-0.85 eV

The energy of an electron in the hydrogen atom in the n^th state is given by 

E_n= -13.6/n²

So, the energy of an electron in the 4^th excited state will be

E₄ = -13.6/(4²) = -0.85 eV