In the case of a common emitter transistor amplifier the ratio of the collector current to the emitter current $I_c / I_e$ is 0.96. The current gain of the amplifier is
Answer & explanation
Correct answer: option 3
$\frac{I_c}{I_e}=0.96⇒I_c=0.96I_c$
But $I_e = I_c + I_b = 0.96I_e + I_b ⇒ I_b = 0.04I_e$
∴ Current gain $β=\frac{I_c}{I_b}=\frac{0.96I_c}{0.04I_e}=24$