A bag contains 4 white and 2 black balls. Another contains 3 white and 5 black balls. If one ball is drawn from each bag, find the probability that both are white?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → \(\frac{1}{4}\)
The draw from one bag does not affect the draw from the other, so the two events are independent, and the probability that both happen is the product of their probabilities.
White from the first bag (4 white out of 6) \(\displaystyle =\frac{4}{6}=\frac{2}{3}\)
White from the second bag (3 white out of 8) \(\displaystyle =\frac{3}{8}\)
Both white \(\displaystyle =\frac{2}{3}\times\frac{3}{8}=\frac{1}{4}\)