If the random variable X has the following probability distribution:
|
X |
0 |
1 |
2 |
Otherwise |
|
P(X) |
K |
3K |
5K |
0 |
then K is equal to
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\frac{1}{9}$
$P(0)=K,\; P(1)=3K,\; P(2)=5K$
Since total probability is $1$:
$K+3K+5K=1$
$9K=1$
$K=\frac{1}{9}$
The value of $K$ is $\frac{1}{9}$.