If the random variable X has the following probability distribution:
| X | 0 | 1 | 2 | Otherwise |
| P(X) | K | 3K | 5K | 0 |
then K is equal to
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → \(\displaystyle\frac{1}{9}\)
The probabilities of a probability distribution add up to 1:
\(K + 3K + 5K + 0 = 1\)
\(9K = 1\)
\( \displaystyle K = \frac{1}{9} \)