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If the random variable X has the following probability distribution:
then K is equal to |
$\frac{4}{9}$ $\frac{2}{9}$ $\frac{1}{9}$ $\frac{8}{9}$ |
$\frac{1}{9}$ |
The correct answer is Option (3) → $\frac{1}{9}$ $P(0)=K,\; P(1)=3K,\; P(2)=5K$ Since total probability is $1$: $K+3K+5K=1$ $9K=1$ $K=\frac{1}{9}$ The value of $K$ is $\frac{1}{9}$. |
