$PQRS$ is a cyclic quadrilateral. If $\angle P$ is 4 times $\angle R $, and $\angle S $ is 3 times $\angle Q$, then the average of $\angle Q$ and $\angle R $ is: |
40.5° 45.7° 90° 81° |
40.5° |
According to question = \(\angle\)P = 4 x \(\angle\)R = \(\angle\)P : \(\angle\)R = 4 : 1 By using the property = \(\angle\)P + \(\angle\)R = 180 = 4x + x = 180 = 5x = 180 = x = 36 = \(\angle\)R = \({36}^\circ\) Now, = \(\angle\)S = 3 x \(\angle\)Q = \(\angle\)S : \(\angle\)Q = 3 : 1 = 3y + y = 180 = 4y = 180 = y = 45 = \(\angle\)Q = \({45}^\circ\) Average of \(\angle\)R and \(\angle\)Q is = (\(\angle\)R + \(\angle\)Q)/2 = \(\frac{36\;+\;45}{2}\) = \(\frac{81}{2}\) = \({40.5}^\circ\) Therefore, the average of (\(\angle\)R and \(\angle\)Q) is \({40.5}^\circ\). |