A pair of adjacent coils has a mutual inductance of 2.0 H. If the current in one coil changes from 0 to 10 A is 0.5 s, the change of the flux linkage with the other coil is |
10 Wb 20 Wb 30 Wb 40 Wb |
20 Wb |
The correct answer is Option (2) → 20 Wb Given: Mutual inductance: $M = 2.0 \, \text{H}$ Change in current: $\Delta I = 10 - 0 = 10 \, \text{A}$ Time interval: $\Delta t = 0.5 \, \text{s}$ Change in flux linkage with the other coil: $\Delta \lambda = M \Delta I$ $\Delta \lambda = 2.0 \times 10 = 20 \, \text{Wb-turns}$ Answer: $\Delta \lambda = 20 \, \text{Wb-turns}$ |