A pair of adjacent coils has a mutual inductance of 2.0 H. If the current in one coil changes from 0 to 10 A in 0.5 s, the change of the flux linkage with the other coil is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \( 20\,\mathrm{Wb} \)
The flux linkage of the second coil due to a current \( I \) in the first coil is \( N\Phi = M\,I \), where \( M \) is the mutual inductance. So the change in flux linkage depends only on the change in current.
\( \displaystyle \Delta(N\Phi) = M\,\Delta I = 2.0\,\mathrm{H} \times (10 - 0)\,\mathrm{A} = 20\,\mathrm{Wb} \)
Note: NTA picked this question from an NCERT (2026-27) exercise and changed the figures. Do not ignore NCERT while practising numericals.
NCERT (2026-27):
Exercises – …
