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$x+\frac{x}{2}+\frac{x}{3}< 11$ |
$(-∞, 7)$ $(-∞, 6)$ $(-∞, 5)$ $(-∞, 4)$ |
$(-∞, 6)$ |
The correct answer is option (2) : $(-∞, 6)$ $x+\frac{x}{2}+\frac{x}{3}< 11$ Multiply by 6 (LCM of 2, 3) both sides $6x+3+2x< 66$ $11x< 66$ $x<6$ Solution is $(-∞, 6)$ |
