The current in a solenoid changes from 0.0A to 10.0A in 0.1 sec. If an average emf of 2V is induced in the circuit, the value of self-inductance is: |
2 H 0.02 H 0.2 H 20 H |
0.02 H |
The correct answer is Option (2) → 0.02 H The induced emf is, $E=-L\frac{dI}{dt}$ $⇒L=\frac{E.dt}{dI}=\frac{0.2}{10.0}=0.02H$ |