The current in a solenoid changes from 0.0A to 10.0A in 0.1 sec. If an average emf of 2V is induced in the circuit, the value of self-inductance is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 0.02 H
The induced emf is,
$E=-L\frac{dI}{dt}$
$⇒L=\frac{E.dt}{dI}=\frac{0.2}{10.0}=0.02H$