In a Young's double-slit experiment, the slits are separated by 0.28 mm and the wavelength of light used is 6000 Å. The fringes are observed on a screen placed 1.4 m away from the slits. The distance between the central bright fringe and the fourth bright fringe will be
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 1.2 cm
Given:
$d = 0.28\ \text{mm} = 0.28 \times 10^{-3}\ \text{m}$
$\lambda = 6000\ \text{Å} = 6000 \times 10^{-10}\ \text{m}$
$D = 1.4\ \text{m}$
Fringe width, $ \beta = \frac{\lambda D}{d}$
$\beta = \frac{6000 \times 10^{-10} \times 1.4}{0.28 \times 10^{-3}} = 3.0 \times 10^{-3}\ \text{m} = 3\ \text{mm}$
Distance of 4th bright fringe from central bright fringe:
$y = n\beta = 4 \times 3 = 12\ \text{mm}$
∴ Distance = 12 mm