If a_ij= i+3j , then the matrix of order 2 with elements as a_ij is

The correct answer is Option (3) → \(\begin{bmatrix}4&7\\5&8\end{bmatrix}\)

Each element is obtained by putting its row number i and column number j into the rule \(a_{ij} = i + 3j\):

    \(a_{11} = 1 + 3 = 4\)
\(a_{12} = 1 + 6 = 7\)
\(a_{21} = 2 + 3 = 5\)
\(a_{22} = 2 + 6 = 8\)

So the matrix is

    \( \displaystyle \begin{bmatrix}4&7\\5&8\end{bmatrix} \)