ABC is an equilateral triangle. P, Q, R are the mid-points of side AB, BC, AC, respectively. If the length of the side of the triangle is 6 cm, then the area of ∆PQR is - 

\(\frac{9\sqrt{3}}{4}\) cm²

A line joining the midpoints of two side is parallel and half of of the third side

Therefore,

⇒ PQ = QR = PR = \(\frac{AB}{2}\) = 3

Area of equilarteral triangle PQR = \(\frac{\sqrt{3}}{4}\) x (3)² =  \(\frac{9\sqrt{3}}{4}\) cm²