An atom bomb weighing 1 kg explodes releasing $9 × 10^{13}$ joule of energy. What percentage of mass is converted into energy?
Answer & explanation
Correct answer: option 3
$E = mc^2 = m \times 9\times 10^{16}= 9 \times 10^{13}$
$m = 10^{-3} kg = 0.1\% \text{ of 1 kg}$