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CUET
General Test
Quantitative Reasoning
Algebra
If x + 3y + 2 = 0 then value of x3 + 27y3 + 8 − 18xy is:
-2
2
1
0
We know that,
If a + b + c = 0,
then a3 + b3 + c3 = 3abc
So, x + 3y + 2 = 0, then
= x3 + 27y3 + 8 - 18xy
= x3 + (3y)3 + 23 - 3 × x × 3y × 2 = 0