If $P(A \cap B) = \frac{7}{10}$ and $P(B) = \frac{17}{20}$, then $P(A \mid B)$ is equal to
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\frac{14}{17}$ ##
Here, $P(A \cap B) = \frac{7}{10}$ and $P(B) = \frac{17}{20}$
$∴P(A \mid B) = \frac{P(A \cap B)}{P(B)} = \frac{7/10}{17/20} = \frac{14}{17}$