If $P(A \cap B) = \frac{7}{10}$ and $P(B

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Target Exam

CUET

Subject

Maths. Section B1

Chapter

Probability

Question:

If $P(A \cap B) = \frac{7}{10}$ and $P(B) = \frac{17}{20}$, then $P(A \mid B)$ is equal to

Options:

$\frac{14}{17}$

$\frac{17}{20}$

$\frac{7}{8}$

$\frac{1}{8}$

Correct Answer:

$\frac{14}{17}$

Explanation:

The correct answer is Option (1) → $\frac{14}{17}$ ##

Here, $P(A \cap B) = \frac{7}{10}$ and $P(B) = \frac{17}{20}$

$∴P(A \mid B) = \frac{P(A \cap B)}{P(B)} = \frac{7/10}{17/20} = \frac{14}{17}$