When an object is shot from the bottom of a long smooth inclined plane kept at an angle 60° with horizontal, it can travel a distance x1 along the plane. But when the inclination is decreased to 30° and the same object is shot with the same velocity, it can travel x2 distance. Then x1 : x2 will be:
Answer & explanation
Correct answer: option 4
x1 = \(\frac{u^2}{2 g Sin 60°}\) ; x2 = \(\frac{u^2}{2 g Sin 30°}\)
x1 : x2 = Sin 30° : Sin 60° = 1 : \(\sqrt{3}\)