Two numbers are in the ratio 9 : 7. If we add 05 in each number then the ratio becomes 5 : 4. Find the least number.

45 35 56 54

35

1st :  2nd = 9 : 7 ATQ, ⇒ \(\frac{9R + 5}{7R + 5}\) = \(\frac{5}{4}\) ⇒ 36R + 20 = 35R + 25 ⇒ 1R = 5 So, Least No. = 7R = 7 × 5 = 35