Practicing Success
The system of equations x + 2y + 3z = 4, 2x + 3y + 4z = 5, 3x + 4y + 5z = 6 has |
Infinitely many solutions No solution A unique solution None of these |
Infinitely many solutions |
Here $Δ=\begin{vmatrix}1&2&3\\2&3&4\\3&4&5\end{vmatrix}=0$, (rows are in AP with common difference 1). Similarly $Δ_x =Δ_y = Δ_z = 0$ Hence (A) is the correct answer. |