A is twice as good a workman as B and together they finish a piece of work in 13 days. In how many days will B alone finish the work?
Answer & explanation
Correct answer: option 1
Given,
A is twice as good a workman as B, therefore,
⇒ A : B = 2 : 1 (Efficiency)
⇒ They both completed the work in 13 days = (2 + 1) x 13 = 39 units, ..(Efficiency × Days = Total work)
⇒ Time required for B to complete the work alone = \(\frac{39}{1}\) = 39 days. ..(\(\frac{Work}{Efficiency}\) = Time)