Practicing Success
A is twice as good a workman as B and together they finish a piece of work in 13 days. In how many days will B alone finish the work? |
39 42 21 18.5 |
39 |
Given, A is twice as good a workman as B, therefore, ⇒ A : B = 2 : 1 (Efficiency) ⇒ They both completed the work in 13 days = (2 + 1) x 13 = 39 units, ..(Efficiency × Days = Total work) ⇒ Time required for B to complete the work alone = \(\frac{39}{1}\) = 39 days. ..(\(\frac{Work}{Efficiency}\) = Time) |