A parallel plate capacitor made of circular plates each of radius 10.0 cm has a capacitance 200 pF. The capacitor is connected to a 200 V ac supply with an angular frequency of 200 rad/s. The amplitude of the current is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (3) → $11.3 \times 10^{-6}$ A
The amplitude of the current in an ac current -
$I=V×ω×C$
$V$ = Voltage Amplitude = 200 V
$ω$ = Angular frequency = 200 rad/s
C = Capacitance = 200 pF
$I=200×200×10^{-12}×200$
$=8×10^{-6}μA$