A parallel plate capacitor made of circular plates each of radius 10.0 cm has a capacitance 200 pF. The capacitor is connected to a 200 V ac supply with an angular frequency of 200 rad/s. The amplitude of the current is:

$8 \times 10^{-6}$ A

The correct answer is Option (3) → $11.3 \times 10^{-6}$ A

The amplitude of the current in an ac current -

$I=V×ω×C$

$V$ = Voltage Amplitude = 200 V

$ω$ = Angular frequency = 200 rad/s

C = Capacitance = 200 pF

$I=200×200×10^{-12}×200$

$=8×10^{-6}μA$