A solid right circular cylinder has height 28 cm and radius of base 7 cm. Two hemispheres of radius 7 cm are cut from both circular ends of the cylinder. What is the total surface area of the remaining portion?

1848 cm²

T.S.A. of remaining portion = C.S.A. of cylinder + C.S.A. of 2 hemisphere

= 2\(\pi \) rh + 2 × 2\(\pi \)r²

= 2\(\pi \) r (h + 2r)

= 2 × \(\frac{22}{7}\) × 7 (28 + 14)

= 44 × 42 = 1848 cm²