In ΔABC, P and Q are points on AB and BC, respectively, such that PQ || AC. Given that AB = 26, PQ = 7 and AC = 10 find the value of AP.
Answer & explanation
Correct answer: option 2
In ΔACB and ΔPCQ
⇒ \(\frac{AC}{CP}\) = \(\frac{AB}{PQ}\)
⇒ \(\frac{26}{CP}\) = \(\frac{10}{7}\)
⇒ CP = 26 x 0.7 = 18.2
As from figure,
⇒ AB = BP + PA
⇒ 26 = 18.2 + AP
⇒ AP = 26 - 18.2 = 7.8 cm
Therefore, AP is 7.8 cm.