A company produces iron rods of mean inner diameter of 2 cm. A sample of 17 rods gives an inner diameter mean 2.01 cm and variance 0.004 $cm^2$ then value of test-statistic is :

0.633

The correct answer is Option (1) → 0.633

The t-test formula is,

$t=\frac{\bar x-\mu}{s/\sqrt{n}}$

$=\frac{2.01-2}{0.0632/\sqrt{17}}$

$=\frac{0.01}{0.01533}≃0.633$