Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Question:

Let X be the greatest number which when divides 2871, 4627 and 7700, the remainder in each case is Y. The value of (x-y) is:

Options:

200

205

202

210

Correct Answer:

202

Explanation:

  4627 - 2871              7700 - 4627

=    1756                       3073

         ↓                             ↓

                 HCF = 439 = X

\(\frac{2871}{439}\) = Remainder 237 = Y

Now, X - Y = 439 - 237 = 202