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What is the last two digits of the product $123×234×345$ |
100 95 85 90 |
90 |
The correct answer is option (4) : 90 $(123×234×345)mod\, 100$ $123=23(mod\, 100)$ $234=34(mod\, 100)$ $345=45(mod\, 100)$ $(123×234×345)=23×34×45(mod\, 100)$ $=3510(mod\, 100)$ $=90(mod\, 10)$ Hence, the last 2 digits of product $123×234×345$ are 90 |
