What is the last two digits of the product 123×234×345

The correct answer is option (4) : 90

$(123×234×345)mod\, 100$

$123=23(mod\, 100)$

$234=34(mod\, 100)$

$345=45(mod\, 100)$

$(123×234×345)=23×34×45(mod\, 100)$

$=3510(mod\, 100)$

$=90(mod\, 10)$

Hence, the last 2 digits of product $123×234×345$ are 90