Arrange the following steps in correct order for rectification using a diode.
A. Input signal is applied.
B. Diode allows current only in one direction.
C. Output becomes pulsating dc.
D. Load resistor receives current in one-direction only.
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → A, B, D, C
A diode rectifies because it conducts only when forward biased, so the current it passes flows one way only. The voltage across the load then rises and falls but never reverses, which is pulsating dc.
(A) Input signal is applied. — the a.c. input is applied first.
(B) Diode allows current only in one direction. — the diode conducts in the half cycles when it is forward biased and blocks the others.
(D) Load resistor receives current in one-direction only. — this one-way current flows through the load resistor.
(C) Output becomes pulsating dc. — the voltage across the load, which is the output, is therefore one-way but pulsating.
So the correct order is A, B, D, C.
NCERT (2026-27):
Application of Junction Diode as a Rectifier – “From the V-I characteristic of a junction diode we see that it allows current to pass only when it is forward biased. So if an alternating voltage is applied across a diode the current flows only in that part of the cycle when the diode is forward biased. … If an alternating voltage is applied across a diode in series with a load, a pulsating voltage will appear across the load only during the half cycles of the ac input during which the diode is forward biased.”