Practicing Success
Practicing Success
CUET Preparation Today
The ratio of the wavelengths for 2 → 1 transition in Li++, He+ and H is : |
1 : 2 : 3 1 : 4 : 9 4 : 9 : 36 3 : 2 : 1 |
4 : 9 : 36 |
$\frac{1}{\lambda}=R Z^2\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right) \Rightarrow \lambda \propto \frac{1}{Z^2}$ $\lambda_{L^{++}}: \lambda_{H e^{+}}: \lambda_H$ = 4 : 9 : 36 |
