Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Application of Integrals

Question:

Let f (x) be a continuous function such that the area bounded by the curve $y = f (x)$, the x-axis, and the lines $x = 0$ and $x = a$ is $1+\frac{a^2}{2}\sin a$. Then,

Options:

$f(\frac{\pi}{2})=1+\frac{\pi^2}{8}$

$f(a)=1+\frac{a^2}{2}\sin a$

$f(a)=a\sin a+\frac{1}{2}a^2\cos a$

none of these

Correct Answer:

$f(a)=a\sin a+\frac{1}{2}a^2\cos a$

Explanation:

It is given that $\int\limits_0^af(x)dx=1+\frac{a^2}{2}\sin a$

Differentiating this with respect to a, we get

$f(a)=a\sin a+\frac{1}{2}a^2\cos a$