If $A = \{x: x^2 -5x+6= 0\}, B = \{2,4\}, C = \{4, 5\}$, then $A×(B∩C)$ is

{(2, 4), (3, 4)} {(4, 2), (4, 3)} {(2, 4), (3, 4), (4, 4)} {(2, 2), (3, 3), (4, 4), (5, 5)}

{(2, 4), (3, 4)}

The correct answer is Option (1) → {(2, 4), (3, 4)} We have, A = {2, 3}, B = {2, 4}, and C = {4, 5} $∴B∩C=\{4\}$ $⇒A×(B∩C)= \{2, 3\} × \{4\} = \{(2, 4), (3, 4)\}$