Find the value of $\frac{tan60°-tan1

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

Find the value of $\frac{tan60°-tan15°}{1+tan60°tan15°}$.

Options:

$\frac{\sqrt{3}}{2}$

$\frac{1}{2}$

$\frac{1}{\sqrt{2}}$

Correct Answer:

Explanation:

We know,

tan ( A - B ) = $\frac{tanA - tanB }{1 + tanA.tanB}$

We have,

$\frac{tan60º - tan15º }{1 + tan60º.tan15º}$

= tan ( 60º - 15º )

= tan 45º

= 1 { tan45º = 1 }